Viết phương trình hoá học thưc hiện các biến hoá dưới đây (mỗi mũi tên là một phản ứng) : Hướng dẫn trả lời: (1) \(C{H_2} = C{H_2} + HCl\) \( \overset{xt}{\rightarrow} \) \(C{H_3} - C{H_2} - Cl\) (2) \({C_2}{H_5}Cl + NaOH\) \( \overset{ancol}{\rightarrow} \) \(C{H_2} = C{H_2} + NaCl + {H_2}O\) (3) \({C_2}{H_5}Cl + NaOH\) \( \overset{nuoc}{\rightarrow} \) \({C_2}{H_5}OH + NaCl\) (4) \({C_2}{H_5}OH + HCl\) \( \overset{t^0}{\rightarrow} \) \({C_2}{H_5}Cl + {H_2}O\) (5) \({C_2}{H_4} + {H_2}O\) \( \overset{H^+}{\rightarrow} \) \({C_2}{H_5}OH\) (6) \({C_2}{H_5}OH\) \( \xrightarrow[170^0c]{H_2SO_4} \) \({C_2}{H_4} + {H_2}O\) (7) \({C_2}{H_5}OH + CuO\) \( \overset{t^0}{\rightarrow} \) \(C{H_3}CHO + Cu + {H_2}O\) (8) \(C{H_3}CHO + {H_2}\) \( \overset{Ni, t^0}{\rightarrow} \) \({C_2}{H_5}OH\) (9) \({C_2}{H_5}OH + {O_2}\) \( \overset{xt}{\rightarrow} \) \(C{H_3}COOH + {H_2}O\) (10) 2\(C{H_3}CHO + {H_2}\) \( \overset{xt}{\rightarrow} \) 2\(C{H_3}COOH\) (11) \(C{H_3}COOH + NaOH \to \) \(C{H_3}COONa + {H_2}O\) (12) \(C{H_3}COONa + {H_2}S{O_4}\) \( \to C{H_3}COOH + N{a_2}S{O_4}\) (13) \(C{H_3}COOH + {C_2}{H_5}OH\) \( \rightleftharpoons \) \(C{H_3}COO{C_2}{H_5} + {H_2}O\) (14) \(C{H_3}COO{C_2}{H_5} + {H_2}O\) \( \rightleftharpoons \) \(C{H_3}COOH + {C_2}{H_5}OH\) (15) \(C{H_3}COO{C_2}{H_5} + NaOH\) \( \overset{t^0}{\rightarrow} \) \(C{H_3}COONa + {C_2}{H_5}OH\)
